Logic Games Bible Workbook, P12:Double Arrow - Biconditional

[LustingFor!L]

I just want to confirm the following rule would be diagrammed as a double arrow:

"If A is not interviewed then B must be interviewed, and if B is interviewed than A cannot be interviewed"

A B
B A

A B

And that diagram means that A will always be with B? So, because this is an in and out grouping game they will never be in the same group?

[LustingFor!L]

Also, this is from the 2017 Edition LSAT Logic Games Bible Workbook in the practice drills on page 12 of Chapter One.

[Dave Killoran]

Hi Lusting,

Think of it more as when ever B is around (B), A won't be there (A). So, in a two group game of any type, if B shows up in a group, A is out. and, via the contrapositive of the underlying rules, whenever a appears in a group, B won't be there. A and B literally will not appear in the same group together.

Thanks!