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Complete Question Explanation
(The complete setup for this game can be found here: lsat/viewtopic.php?t=6748)

The correct answer choice is (E)

If T were the first report in the first segment, then N must be the first report in the second segment, because N is the longest of the five reports:
PT72_Game_#1_#6_diagram 1.png
The implications of this setup are not immediately clear, which is why it would be useful to establish two local diagrams—one where S is the last report in the first segment, and one where S is the last report in the second. Remember: if you do not know how to proceed with your local setup, look for Dual Options that you can exploit to your advantage! Creating two local diagrams is still a more efficient way to spend your time than using a single diagram to account for the various positions in which the three remaining variables can be placed:
PT72_Game_#1_#6_diagram 2.png
PT72_Game_#1_#6_diagram 3.png
In the first solution, we need to ensure that the second segment contains at least one report of local interest. That report can be none other than W. I, therefore, must be the second report in the first segment:
PT72_Game_#1_#6_diagram 4.png
In the second solution, both I and W are forced into the first segment. To comply with the last rule of the game, I must be second, and W—third:
PT72_Game_#1_#6_diagram 5.png
These solutions prove that W can be the last report in the second sequence, validating answer choice (E). None of the remaining four answer choices can be true.

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