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 Dave Killoran
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Complete Question Explanation
(The complete setup for this game can be found here: lsat/viewtopic.php?t=13387)

The correct answer choice is (C)

Hannah visits four cities collectively in X and Y; she must minimize her visits in X to maximize her visits in Y. She must visit at least one city in each country, so Hannah should visit one city in X, allowing her to visit three cities in country Y.

We should again consider the Days-to-Cities distributions to determine how much time she can spend in country Y’s three cities:

  • Using the 4-2-2-2-2-2 distribution, she could spend 4 days in a city, 2 days in another city, and 2 days in the third city, for a total of eight days.

    Using the 3-3-2-2-2-2 distribution, she could spend 3 days in each of two cities, and 2 days in a third city, for a total of eight days.
With either distribution, the most time Hannah could spend in country Y would be eight days, so choice (C) is the correct answer choice.

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