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- Fri Nov 03, 2017 4:01 pm
#41181
Setup and Rule Diagram Explanation
This is a Basic Linear: Balanced game.
The variables and basic setup to this game can be diagrammed as follows:
The first rule establishes R Not Laws on the first and last houses on the street, and the second rule establishes that K is the fourth house on the street:
The third rule establishes a MK or KM block. Because there are two options for this block but K is already fixed, this is shown as a dual-option for M. In addition, because M is not completely fixed, we will show the M Not Laws on houses 1, 2, 6, and 7:
Finally, the last rule produces a sequence that appears as follows:
This sequence produces a number of Not Laws for P and L, in particular that P and L cannot occupy any of the first three houses, and that L cannot be fifth and that P cannot be last (because P L):
As always, before moving on to the questions make sure to check the restrictions within the game. The first house has the greatest number of Not Laws, so take a moment to examine the possibilities for the first house. The first house cannot be occupied by K because K is already placed, and also cannot be occupied by R, M, P, and L due to Not Laws. Thus, only N or O remain to occupy the first house, an inference that plays a significant role within the game. Adding this information to the game leads to the final setup:
Notes:
N and O are randoms (despite the fact that they appear on the diagram; this is a result of the actions of the other rules, not from a specific rule involving N or O), and are noted with asterisks.
As a result of the combination of the second, third, and fourth rules, we can infer that P must live in either the fifth house or the sixth house, and L must be in either the sixth house or the seventh house. This occurs because the P L sequence must be to the east of the MK block, leaving P L to fit into the fifth, sixth, and seventh houses. Although P and L options could be added to the diagram, doing so could be confusing because a P/M dual-option would appear on house 5, when it is also possible that others could occupy the house.
Also, if M lives in the fifth house, then P lives in the sixth house and L lives in the seventh house.
This is a Basic Linear: Balanced game.
The variables and basic setup to this game can be diagrammed as follows:
The first rule establishes R Not Laws on the first and last houses on the street, and the second rule establishes that K is the fourth house on the street:
The third rule establishes a MK or KM block. Because there are two options for this block but K is already fixed, this is shown as a dual-option for M. In addition, because M is not completely fixed, we will show the M Not Laws on houses 1, 2, 6, and 7:
Finally, the last rule produces a sequence that appears as follows:
This sequence produces a number of Not Laws for P and L, in particular that P and L cannot occupy any of the first three houses, and that L cannot be fifth and that P cannot be last (because P L):
As always, before moving on to the questions make sure to check the restrictions within the game. The first house has the greatest number of Not Laws, so take a moment to examine the possibilities for the first house. The first house cannot be occupied by K because K is already placed, and also cannot be occupied by R, M, P, and L due to Not Laws. Thus, only N or O remain to occupy the first house, an inference that plays a significant role within the game. Adding this information to the game leads to the final setup:
Notes:
N and O are randoms (despite the fact that they appear on the diagram; this is a result of the actions of the other rules, not from a specific rule involving N or O), and are noted with asterisks.
As a result of the combination of the second, third, and fourth rules, we can infer that P must live in either the fifth house or the sixth house, and L must be in either the sixth house or the seventh house. This occurs because the P L sequence must be to the east of the MK block, leaving P L to fit into the fifth, sixth, and seventh houses. Although P and L options could be added to the diagram, doing so could be confusing because a P/M dual-option would appear on house 5, when it is also possible that others could occupy the house.
Also, if M lives in the fifth house, then P lives in the sixth house and L lives in the seventh house.
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Dave Killoran
PowerScore Test Preparation
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PowerScore Test Preparation
Follow me on Twitter at http://twitter.com/DaveKilloran
My LSAT Articles: http://blog.powerscore.com/lsat/author/dave-killoran
PowerScore PodCast: http://www.powerscore.com/lsat/podcast/