- Sat Jan 21, 2012 12:00 am
#25647
Complete Question Explanation
(The complete setup for this game can be found here: lsat/viewtopic.php?t=7800)
The correct answer choice is (D)
This question stem establishes that T is visited fifth. Since the same destination cannot be visited
in two consecutive weeks, it follows that T cannot be visited fourth. Additionally, visiting J
requires the creation of a GJ Block, which would be impossible if J were visited six:
At this point, it would be critical to focus on the most restricted variable in our game – J. J cannot
be visited fourth (first rule), and it also cannot be visited first as a result of the fourth rule.
Therefore, J must be visited either second or third, but not both (which would violate both the
fourth and the fifth rules). In either case, we must ensure that G is visited immediately before J:
At this point, we need to consider the M > G > M sequence. In the first local diagram above, the
sequence can be satisfied if G is also visited fourth (remember – each destination can be visited
more than once):
In the second local diagram, M must be visited first, and again either fourth or sixth. If M is
visited fourth, the sixth destination would be none other than G; likewise, if M is visited sixth, the
fourth destination must be G:
These solutions show that answer choice (D) could be true, as M could be visited fourth. None of
the other answer choices are possible under the condition established by the question stem.
(The complete setup for this game can be found here: lsat/viewtopic.php?t=7800)
The correct answer choice is (D)
This question stem establishes that T is visited fifth. Since the same destination cannot be visited
in two consecutive weeks, it follows that T cannot be visited fourth. Additionally, visiting J
requires the creation of a GJ Block, which would be impossible if J were visited six:
At this point, it would be critical to focus on the most restricted variable in our game – J. J cannot
be visited fourth (first rule), and it also cannot be visited first as a result of the fourth rule.
Therefore, J must be visited either second or third, but not both (which would violate both the
fourth and the fifth rules). In either case, we must ensure that G is visited immediately before J:
At this point, we need to consider the M > G > M sequence. In the first local diagram above, the
sequence can be satisfied if G is also visited fourth (remember – each destination can be visited
more than once):
In the second local diagram, M must be visited first, and again either fourth or sixth. If M is
visited fourth, the sixth destination would be none other than G; likewise, if M is visited sixth, the
fourth destination must be G:
These solutions show that answer choice (D) could be true, as M could be visited fourth. None of
the other answer choices are possible under the condition established by the question stem.