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 Dave Killoran
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#45473
Complete Question Explanation
(The complete setup for this game can be found here: lsat/viewtopic.php?t=4541)

The correct answer choice is (D)

Because all four flower types must be used, to maximize roses simply minimize the other three types by using them once each. As discussed in the game setup, six roses is the maximum, and answer choice (D) is correct.
 destaat
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#6218
Number 2.

The answer is D.

However if there were 6 roses that would mean there were 3 orchids. Together this takes up all 9 spots. An there should be at least one of each flower types, including one g in corsage 3. Someone help me figure this out.


Thank you for all your help powerscore. It's been more than helpful.
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 Dave Killoran
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#6225
Hi A.T.,

This is one that will bother you after you see it. Go back and re-read that rule about the number of orchids and roses. It doesn't say exactly twice as many, but rather that the number of roses is at least twice the number of orchids.

The presence of “at least” in the game scenario makes the number of distributions more difficult to determine (there are 7 possible combinations of roses and orchids). Had the condition specified “exactly” instead of “at least,” the distributions could have been quickly and easily fixed at 2-1 and 4-2 (and 6-3 would be impossible since, as you correctly note, it would take up all 9 spots).

Please let me know if that helps, and thanks for the compliments! They are definitely appreciated!
 destaat
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#6269
That is annoying. I got it. Thank you.
 Blueballoon5%
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#47346
Dave Killoran wrote:Hi A.T.,

This is one that will bother you after you see it. Go back and re-read that rule about the number of orchids and roses. It doesn't say exactly twice as many, but rather that the number of roses is at least twice the number of orchids.

The presence of “at least” in the game scenario makes the number of distributions more difficult to determine (there are 7 possible combinations of roses and orchids). Had the condition specified “exactly” instead of “at least,” the distributions could have been quickly and easily fixed at 2-1 and 4-2 (and 6-3 would be impossible since, as you correctly note, it would take up all 9 spots).

Please let me know if that helps, and thanks for the compliments! They are definitely appreciated!
Hi Dave! I am having some English problems (English is not my first language). By "at least twice," does this mean, for example, if I have 2 orchids, I must have 4,5,6,7,... (or so on) roses?
 Rachael Wilkenfeld
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#62617
Hi Blueballoon,

Exactly! By at least twice, we treat two times the number of orchids as the minimum number of roses. So if there is 1 orchid, there needs to be at least 2 roses. There could be 3, 4, 5, or 6 roses, and still fit the rule. Similarly, if there are 2 orchids, you must have a minimum of 4 roses, but you could still have 5 and comply with all the rules.

Hope that helps!
Rachael

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