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- Sat May 05, 2018 1:26 pm
#45480
Complete Question Explanation
(The complete setup for this game can be found here: lsat/viewtopic.php?t=2408)
The correct answer choice is (B)
If only one experiment is performed and no red flasks remain, then the original red flask (flask 1) must have been used in the experiment. Flask 1 cannot be mixed with flask 2 because that would produce a red chemical, so the experiment must be either 1 + 3 (leaving 2 and 4 unused, producing a B, B, O result), or 1 + 4 (leaving 2 and 3 unused, a G, B, G result). Answer choice (B) is correct because it presents B, G, G (2, 1 + 4, 3). This is possibility #5 in the master list.
(The complete setup for this game can be found here: lsat/viewtopic.php?t=2408)
The correct answer choice is (B)
If only one experiment is performed and no red flasks remain, then the original red flask (flask 1) must have been used in the experiment. Flask 1 cannot be mixed with flask 2 because that would produce a red chemical, so the experiment must be either 1 + 3 (leaving 2 and 4 unused, producing a B, B, O result), or 1 + 4 (leaving 2 and 3 unused, a G, B, G result). Answer choice (B) is correct because it presents B, G, G (2, 1 + 4, 3). This is possibility #5 in the master list.
Dave Killoran
PowerScore Test Preparation
Follow me on Twitter at http://twitter.com/DaveKilloran
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PowerScore Test Preparation
Follow me on Twitter at http://twitter.com/DaveKilloran
My LSAT Articles: http://blog.powerscore.com/lsat/author/dave-killoran
PowerScore PodCast: http://www.powerscore.com/lsat/podcast/