#11 - Local, Must Be True

[Dave Killoran]

Complete Question Explanation
(The complete setup for this game can be found here: lsat/viewtopic.php?t=16326)

The correct answer choice is (B)

As you might expect in a game with only five questions, the last question is relatively hard. The key word in the question stem is “only.” Since G is the only child in group 1, there must be two adults in group 1. Also, since G is involved in one of our primary inferences, we know that when G is in group 1 then T must be in group 3:

O94_Game_#2_#11_diagram 1.png

However, we can continue to make inferences because of the limited number of remaining spaces. The four remaining children, F, J, H, and K must be split between groups 2 and 3. Since F and J are a block, H and K must also form a block for this question. Since H cannot be placed into group 2, the H and K block must be placed into group 3, and F and J must then be placed into group 2:

O94_Game_#2_#11_diagram 2.png

These final inferences provide the justification for answer choice (B), the correct answer. Note that the
positions of three remaining adults, Q, R, and S cannot be determined. Some students select answer choice (D), using the inference regarding H and R to incorrectly assume that since H is in group 3,
then R must be in group 1. This is the Mistaken Reversal of the original inference and is thus incorrect.

As mentioned at the beginning of the setup discussion, the concepts in this game type have appeared repeatedly on recent LSAT’s, and thus we strongly recommend that you work with this game and others like it until you have mastered these concepts.