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 Alex Bodaken
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Thanks for the question! From our diagram, we know that N has to be assigned to the front row (we have not laws prohibiting it from being in the middle and back rows). We also know that neither S nor U can be next to N from our not blocks. Therefore, S and U can't be in seat 2 either because N will be there or because N will be in seats 1 or 3, meaning that the S or U in seat 2 would be next to N, thereby violating our not blocks.

Hope this helps!
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I was wondering how we can infer N is in the first row. Why couldn't N be in the middle row and RPX/XPR be in the last row?
 Adam Tyson
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Thanks for the question and welcome to the Forum, ep3491! If RPX were in the last row, there would no room for O back there, violating the first rule. Be sure to take into account all the rules! Think of them like a series of filters, and every correct answer has to be run through those filters to be sure it complies with them all. Ideally we should be able to do that by just looking at our diagram (in this case, seeing O next to that last row should do the job), but any time we are unsure we have the luxury of being able to just look at the list or rules on the screen and using those in order. Did I comply with rule 1? Rule 2? Rule 3? Filter out the problems and come out with a winner!

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