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- Joined: Jan 09, 2017
G2 = G1 Thus, -- G G G (Light bulb three must be G because if not, it would be yellow or purple which would make light bulb 2 purple, which is impossible if G must be 2. However, G could still be first without G in second because of the contrapositive laws, no? Of course, then purple would be second with Y/P in third.
One last thing, I see in the initial scenario that there are three of each light bulb. I diagrammed the light bulbs as
At first, I did not understand the meaning of this but now I understand. It serves to show that, conceivably, the three sockets could be filled with one color light bulb?