#4 - Local, Could Be True

[Dave Killoran]

Complete Question Explanation
(The complete setup for this game can be found here: lsat/viewtopic.php?t=16021)

The correct answer choice is (B)

If Q is assigned to table 1, P and Z must be assigned to table 3:

Since the question stem also states that table 1 has three sponsors, the numerical distribution is now fixed at 3-2-2:

Since the four remaining unseated sponsors are K, M, L, and V, two of that group must sit at table 1 and the other two must sit at table 2. Because L and V must sit together as a block, it follows that K and M must also sit together as a block. Thus, the KM block and the LV block cannot sit together:

This information is sufficient to prove answer choice (B) correct.