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- Joined: Apr 14, 2011
Start by looking at the numerical distribution in the game, which they are kind enough to spell out for you with the first 4 rules. Group R has just 1 variable, Groups S and T have two each, and Group Y has three.
Next, since neither P nor L can be in the same group as G, we can infer that G is NOT among the variables in Group Y. That group has to be H, L and P.
Also, while it doesn't end up impacting this particular question, G cannot be in Group R either, because the last rule requires that anywhere G goes, H must also go.
Now, think about each answer in q9 and, in the cases of answers A and B ask yourself "what could the other variable in Group S be?" It can't be anything else that appears in Group Y, because then we wouldn't have a complete list of the variables that those two groups have in common.
For answer A, the other variable in Group S could be G. That is, Group S could have H and G in it while Group Y has HLP in it, and the only variable in both is H. Answer A therefore could be true, and is therefore a wrong answer.
What about answer B now? If P is in Group S, what could you pair it with? Not G - that violates one of the rules. If we tried to pair it with H or L, then P would NOT be the only variable that is in both S and Y. That's why B is the correct answer.
Hope that cleared things up!
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