#22 - Local, Cannot Be True

[Dave Killoran]

Complete Question Explanation
(The complete setup for this game can be found here: lsat/viewtopic.php?f=282&t=7598)

The correct answer choice is (B)

If H is not featured on day 7, then only Template #4 applies:

G4-Q22-d1.png

As days 2 and 6 have established pairs of puppies and kittens that are different, answer choice (B) is the correct answer.

[SherryZ]

Hi there, thank you for helping me out!

Oct 2000 LSAT,Q22.

Q22 assumes when H is NOT on day 7. So according to one of the possibilities:

K: _ H _ H _ H _
P: G _ _ _ _ _ N
1 2 3 4 5 6 7

Could you tell me whether this set up is right? If it is right, then WHY Q22's answer is B? According to my set up, both day 2 and day 6's kittens are H, this violates the stimulus.

Thank you very much!!

---Sherry

[Lucas Moreau]

Hello, Sherry,

For #22, your setup is indeed correct. But we know that H and R can never be on the same day together, so that tells us that the Day 2 dog must be N (can't be G because it's next to a G, can't be R), and the Day 6 Dog must be G (can't be N because it's next to an N, can't be R). So that's why B is correct.

Hope that helps,
Lucas Moreau
PowerScore