### #18 - Local, Must Be True

Posted:

**Tue Jun 14, 2016 1:12 pm**Complete Question Explanation

(The complete setup for this game can be found here: lsat/viewtopic.php?t=11096)

The condition in the question stem creates an F __ __ O block. Consequently, O cannot be performed first, and O must be performed fifth (and F must be performed second). From the second rule, we know that at least two compositions must separate R and F, and since F is second, we can conclude that R must be sixth or seventh. This information eliminates answer choices (A), (B), and (C). If R is performed seventh, then from the first rule we can conclude that T is performed first, and from the last rule we can conclude that S is performed third. But, if S is performed third, then there is no room for P to be performed before S, and the fifth rule is violated. Hence, R cannot be performed seventh, and R must be performed sixth.

(The complete setup for this game can be found here: lsat/viewtopic.php?t=11096)

**The correct answer choice is (D)**The condition in the question stem creates an F __ __ O block. Consequently, O cannot be performed first, and O must be performed fifth (and F must be performed second). From the second rule, we know that at least two compositions must separate R and F, and since F is second, we can conclude that R must be sixth or seventh. This information eliminates answer choices (A), (B), and (C). If R is performed seventh, then from the first rule we can conclude that T is performed first, and from the last rule we can conclude that S is performed third. But, if S is performed third, then there is no room for P to be performed before S, and the fifth rule is violated. Hence, R cannot be performed seventh, and R must be performed sixth.

**Answer choice (D) is thus correct.**