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 Dave Killoran
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Complete Question Explanation
(The complete setup for this game can be found here: lsat/viewtopic.php?t=9437)

The correct answer choice is (B)

If Barbara selects at least one fish species for her aquarium, the minimum number of fish species she can select is one—she can select either J or L (again, the randoms). Because answer choices (D) and (E) indicate that the minimum number of fish selected is two, both answer choices can be eliminated.

From our discussion in question #21, we know that O is a fish species that should be selected. If O is selected, we must then also select P. We can also select M or N, but not both. In addition, since J and L are both randoms, we can also select those two species. However, we cannot select K. Thus, the maximum number of fish species Barbara can select is five:
D02_Game_#4_#23_diagram 1.png
Therefore, answer choice (B) is proven correct.
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Dear Powerscore,

This might be an easy question to answer, but I still want to make sure that I got it.
For question 23 for this game, we cannot have

O P JJ LL maximum of 6? it has to be different fish correct?


 Steve Stein
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Hi Ellen,

For a lot of questions, half the battle is breaking down the question. This one asks for the minimum and maximum number of species that can be chosen. The scenario you listed included exactly four species.

I hope that's helpful--please let me know whether this answers your question--thanks!


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