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Complete Question Explanation
(The complete setup for this game can be found here: lsat/viewtopic.php?t=6788)

The correct answer choice is (B)

Like the other Global questions in this game (#6 and #7), this question can be time-consuming. Remember, on many Global questions using hypotheticals is a fast and effective method of attack.

Answer choice (A) is proven incorrect by the hypothetical provided in question #6.

Answer choice (B) is the correct answer choice. If the condition in the answer choice is true, then only three sessions would be attended by the employees (two sessions per employee and two employees at each session equals three sessions of two employees each). However, there is no acceptable scenario where this can occur because none of the employees can repeat a session topic.

Answer choice (C) is proven incorrect by the following hypothetical:
D02_Game_#2_#9_diagram 1.png
D02_Game_#2_#9_diagram 1.png (4.45 KiB) Viewed 939 times
Answer choices (D) and (E) are functionally identical, and therefore both are incorrect. M and S are basically interchangeable, and these two answers simply pair S with T, and then M with T. If S can pair with T, then logically M can pair with T. According to the Uniqueness Theory of Answer Choices, each correct answer choice is identifiably unique, and so any pair of functionally identical answer choices must be incorrect.
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So, I chose "E' for this answer choice. I reasoned, that of the three employees, Tate is the only one that is not restricted to any sessions, while the other two are to hiring and regulations. So, if T was to attend investing, then this would most certainly be false? So, while answer choice B is the right answer, does answer choice B take precedence over E for the simple reason that, while you can make E can be true, B under no circumstance would be true?

If that is the case, then why isn't the "every" in answer choice E scrutinized to the degree that would reflect this answer choice to be right as well?
 Malila Robinson
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Hi Pragmatism,
The question stem is saying that 4 of the answer choices Could Be True and the one correct answer choice Cannot Be True. As the Admin explained (above) there is no scenario where B could work which makes it the correct answer. As you pointed out, E could be true so it is not the correct answer.
Hope that helps!
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Could someone draw out the diagram as explained by Answer Choice B? Thank you.
 Robert Carroll
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I wish I could! But note what the question is asking: "Each of the following is possible EXCEPT". In other words, every wrong answer is something that it is possible to do. The correct answer, then, will be the one answer that is not possible. So no one can create a diagram that makes answer choice (B) work, and that's exactly why it's the correct answer for this question.

Let's talk a little more about why answer choice (B) can't happen.

As the explanation that starts this thread says, if answer choice (B) is true, then exactly three sessions would be attended by the employees, each session attended by a pair of employees. Let's think about those pairs. What if M and S never attend together? Then each attends once with T, and there are only two sessions possible (MT and ST). That's not allowed - we need exactly three sessions, as noted.

So let's try again. What if M and S attend together twice? Then T can never pair up with them, so, again, we will not have three sessions of two people each, as required.

So what must happen is that M and S attend together exactly once, then each attends something with T. So our pairs of people attending the three sessions are as follows: MS, MT, ST. T does nothing on the third day, so the MT and ST sessions are on the first and second days, in either order. Because M and S cannot attend investing, the MT and ST sessions must be on hiring and regulations; they can't be on the same topic, because then T would be repeating a topic.

So, at this point, we have MT attending hiring or regulations together on day 1 or day 2, and ST attending regulations or hiring together on day 2 or day 1. We need MS to attend something together. But it can't be on hiring - either the MT or the ST pair already did that, so one of the pair MS is not excluded from hiring. But it also can't be regulations for the same reason. So MS can't attend anything without violating some rule.

This is why answer choice (B) does not work.

Robert Carroll

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