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- Fri Oct 12, 2018 1:58 pm
#59495
Complete Question Explanation
(The complete setup for this game can be found here: lsat/viewtopic.php?t=26462)
The correct answer choice is (A)
If T plays in the fourth game, then only Template #1 can apply to this question. Let’s revisit template #1 with the addition of T in the fourth game:
The variables yet to be placed include N, P, and the choice of L, P, or T, but there is no way to place those remaining variables exactly. So, although you might wish you could derive more information as a consequence of the placement of T, there are still a number of possibilities and you must move forward and attack the answer choices without getting bogged down trying to assign every player.
Answer choice (A): This is the correct answer choice. N could play in the second game as proven in the following hypothetical:
Answer choice (B): This answer choice cannot be true because O plays only once, in the second game.
Answer choice (C): This answer choice is incorrect because S must play in the first and third games, not the second game.
Answer choice (D): This answer choice is incorrect. N can only play in one game, and N’s choices for playing partners are S or O (that is, the only open spaces in the diagram are paired with S or O). Thus, N cannot play with L.
Answer choice (E): This answer choice is similar to answer choice (D). Although P can play in more than one game, there is no possibility of P playing with L. As with (D), the only open spaces in the diagram are paired with S or O. Thus, P cannot play with L, and this answer is incorrect.
(The complete setup for this game can be found here: lsat/viewtopic.php?t=26462)
The correct answer choice is (A)
If T plays in the fourth game, then only Template #1 can apply to this question. Let’s revisit template #1 with the addition of T in the fourth game:
The variables yet to be placed include N, P, and the choice of L, P, or T, but there is no way to place those remaining variables exactly. So, although you might wish you could derive more information as a consequence of the placement of T, there are still a number of possibilities and you must move forward and attack the answer choices without getting bogged down trying to assign every player.
Answer choice (A): This is the correct answer choice. N could play in the second game as proven in the following hypothetical:
Answer choice (B): This answer choice cannot be true because O plays only once, in the second game.
Answer choice (C): This answer choice is incorrect because S must play in the first and third games, not the second game.
Answer choice (D): This answer choice is incorrect. N can only play in one game, and N’s choices for playing partners are S or O (that is, the only open spaces in the diagram are paired with S or O). Thus, N cannot play with L.
Answer choice (E): This answer choice is similar to answer choice (D). Although P can play in more than one game, there is no possibility of P playing with L. As with (D), the only open spaces in the diagram are paired with S or O. Thus, P cannot play with L, and this answer is incorrect.
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Dave Killoran
PowerScore Test Preparation
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PowerScore Test Preparation
Follow me on Twitter at http://twitter.com/DaveKilloran
My LSAT Articles: http://blog.powerscore.com/lsat/author/dave-killoran
PowerScore PodCast: http://www.powerscore.com/lsat/podcast/