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## #14 - Local, Could Be True

Dave Killoran
• PowerScore Staff
• Posts: 5786
• Joined: Mar 25, 2011
#44075
Complete Question Explanation
(The complete setup for this game can be found here: lsat/viewtopic.php?t=6217)

The correct answer choice is (B)

If only one store carries F that store must be X. That means that S carries J, O, and R. Also, V and Z must carry R and O, with R/O split between them (1 type each).

Answer choice (A) is incorrect because V carries only 1 type.

Answer choice (B) is the correct answer choice. S and T both carry R and O.

Answer choice (C) is incorrect because V carries only 1 type.

Answer choice (D) is incorrect because V carries only 1 type.

Answer choice (E) is incorrect because Z carries only 1 type.
AlwaysPreppin
• Posts: 2
• Joined: May 27, 2023
#101957
I may definitely be missing something here, but this question held me up way longer than it should have due to the following:

I see only one possibility for S and T given these Local conditions - which is J, O, and R in the S group and O and R in the T group. Therefore I identified answer choice B as a 'Must Be True' scenario, and due to the common trap of terms of truth, I sunk time into finding a 'Could Be True' answer (unsuccessfully).

Is answer choice B correct because Must Be True scenarios fall under the umbrella of Could Be True scenarios? Or am I missing an alternate possibility for S and/or T?