- Fri Mar 08, 2019 6:27 pm
Z isn't really random here, LSAT20148, because it is in the rule about U having to be paired with something. Other than that, I think you're looking pretty good here! You've identified the numerical distributions of 2-2-2 or 3-2-1 (unfixed).
I think you will find that there are many more possibilities to this game, and I wouldn't chase them all down, especially since there are only 5 questions. Don't box yourself in by thinking that these are all there are, but instead use them as a jumping off point to help you understand the game overall a little better. I didn't see any major inferences in this game, and I only chose to do a single hypothetical before heading to the questions. I based it on the 2-2-2 distribution since I saw that it really boxed U in tightly:
T would have to be in the first spoonful, U in the second, X in the third. either Y or Z would go with U. W would have to go with T since it couldn't be in the last spoonful, and then the leftover of Y and Z would go with X in the last spoonful. So it looks like this:
TW - U Y/Z - X Z/Y
Two solutions, one template, and that covers the 2-2-2. For the 3-2-1 I could see that there were too many choices for which group was what size, so I just moved to the questions figuring I'll work those out when and if I need to. That happened, for example, on question 19, where I worked out a 2-1-3 and a 2-3-1 to see what could happen when Y was alone.
Adam M. Tyson
PowerScore LSAT, GRE, ACT and SAT Instructor
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