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## #22 - Local, Must Be True

Dave Killoran
• PowerScore Staff
• Posts: 4740
• Joined: Mar 25, 2011
#88142
Complete Question Explanation
(The complete setup for this game can be found here: lsat/viewtopic.php?f=167&p=88139#p88139)

The correct answer choice is (C).

The question stem specifies that G is the second passenger to exit, and that L and S are the first two stops, not necessarily in that order:

Of course, if L and S are the first two stops, then F and M must be the last two stops, in some order. If M is third or fourth, then from the second rule we can infer that R cannot be first, and must be third or fourth. From the third rule J cannot be first, and so the only passenger who is available to exit first is V. With V exiting first, J and R must exit third and fourth, not necessarily in that order. Thus, without accounting entirely for the second and fourth rules, this is the current setup for this question:

While the actions of the second and fourth rules limit the number of solutions possible under the scenario above, the information thus far is sufficient to answer this question. Because S is the first or second stop, and R must exit third or fourth, answer choice (C) must be true and is correct.

The following hypothetical eliminates answer choices (A) and (D):

The following hypothetical eliminates answer choice (B):

The following hypothetical eliminates answer choice (E):

josuecarolina
• Posts: 24
• Joined: Jul 20, 2012
#22138
Hi,

Can you explain #22?

Thank you!
Nicholas Bruno
• PowerScore Staff
• Posts: 62
• Joined: Sep 27, 2011
#22139
Hi,
First, I would recommend that you read a prior post about the setup lsat/viewtopic.php?f=167&t=8582.

22) We know that G is not greater than S so J cannot be greater than F. We also know that G is second.

With G second, we know that L and S are the first two stops since G has to be on the bus at both stops. This leads us to know that R must be third or forth since it must not be before M. We know that J cannot be first (since V must come after it). This leaves only V for the first spot.

The diagram would look like:

V G R/J R/J
L/S L/S F/M F/M

A is wrong: V is not necessarily on the bus when the bus gets to S.
B is wrong: same as A
C: correct - we know R will be on the bus until S has passed
D: we do not know this - R could get off at M - with both at stop 3
E: same explanation as D.

Let me know if this helps you out!
eober
• Posts: 107
• Joined: Jul 24, 2014
#22130
Hi,

How did we set up the template in this game. I had a very poorly constructed template for this game and I couldn't solve #22. Could you explain what the best way to diagram this game would be?

Thanks!
David Boyle
• PowerScore Staff
• Posts: 836
• Joined: Jun 07, 2013
#22131
Hello,

One way to set it up:

la 1,2 (or putting la/, /la over spaces 1, 2)
m r still on board (though she could presumably get off at m)
v > j (v gets off before j)
f + j on board s + g on board

For question 22, since la and s must be in the first two, if g gets off second, then m must be in space 3 or 4. So r must still be on board at s, since she has to get off later, at m or after. (Answer C)

Hope that helps,
David
eober
• Posts: 107
• Joined: Jul 24, 2014
#22132
Makes perfect sense, thanks!
angelsfan0055
• Posts: 31
• Joined: Feb 26, 2021
#91591
Hi, this question was difficult for me, and I'm not sure I'm grasping the explanation. how do we know from the Stem that Greg is second? I also was not sure if this was a local or global question based on how it was worded. I ended up choosing B based on a previous hypothetical