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 Dave Killoran
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#86317
Complete Question Explanation
(The complete setup for this game can be found here: lsat/viewtopic.php?t=14889)

The correct answer choice is (A).

If both parks are planted with S, then G has all three variety spaces planted (M, S, and T). L must be planted with at least S and T, and the remaining variety planted in L can be either M or O:
PT56-Dec2008 LG Explanations_game_#3_#14_diagram 1.png
As the number of parks planted with M can equal the number of parks planted with O (one M in G, one O in L), answer choice (A) could be true and is correct.
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