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 Adam Tyson
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#22616
I'm basing my answer solely on the diagrams laid out here, and the answer to your question is "yes!" If E is offered, A must be not offered, and if A is not offered then neither O nor S may be offered.

Well done!
 kumarshe
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#26133
I also wanted to know if my inference for the game on pg. 300 (question #2) is correct. I was struggling with it a bit.

Since A :arrow: F + —E I divided the statement into two A :arrow: F and A :arrow: —E
Since L :arrow: E + —M I divided the statement into two as well L :arrow: E and L :arrow: —M
I then combined L :arrow: E :dblline: A = L :dblline: A

Thanks,

Shefali
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 Dave Killoran
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#26135
Yes, that is correct, and it matches the inference shown in the book on page 309. So, good work there!

Note: you don't have to separate out these statements into the sub-components; only do it if you find that it helps to make the game more sense. Since the sub-component relationships reflect the truth of the initial, more complex statement, you can use either to make inferences. It's all about what is easiest for you.

Thanks!
 mp1224
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#48898
Hello,

For the second question of the Grouping Setup Practice Drill in Chapter 5 ("A business school offers at least one of the following seven courses..."), I was wondering how you would diagram the contrapositives for the first two rules - A :arrow: F and not E; L :arrow: E and not M.

Thank you!
 mp1224
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#48923
Hi Dave,

Thanks for the reply!

On a similar note, in the case of a conditional statement such as "If M is selected, then neither J nor O can be selected" (p. 410), instead of diagramming this rule as: M :dblline: J and M :dblline: O, would it also be correct to depict it as:

M :arrow: J and O ?

If this is also correct, what is the reasoning behind choosing to depict it the first way over the second?
 Adam Tyson
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#49012
That would also be correct, mp1224, so good job there! We choose to show it with two double-not arrows because they save us the trouble of having to diagram a contrapositive, and because for many students splitting the rule into two rules this way makes it much easier to manage. No worrying about converting "and" to "or", and no mistakenly assuming that the necessary conditions have any relationship to each other. It becomes "these two cannot be selected together" and also "those two cannot be selected together" - boom, done!

That said, your diagram is correct, and you would at least want to consider the contrapositive, if not actually draw it out in your diagram. That would be:

J
or :arrow: M
O

Play around with both approaches and use whichever one you find more useful and efficient!
 kg70382
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#58049
On page 320, I'm not sure how the sub-inferences were derived. Can you explain the steps of how the inferences for O and E cannot be selected together, S and E cannot be selected together, If O then F, and If S then F were made?

Also, What is the procedure/logic behind linking conditional statements with two sufficient conditions, two necessary conditions, or both? For example: How would I link (If O or S then A) with (If A or B then C)? Does the presence of the "or" or "and" effect how the statements can be linked?

Thank you in advance.
 Adam Tyson
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#58104
You bet, kg70382! Here are the steps for making those inferences:

First, we have the last rule: if either O or S is offered, then A must also be offered.

Then, we link that rule to the first rule: if A is offered, F is offered and E is not offered.

That gives us this chain (which should also help answer your second question):

O                         F
or :arrow: A :arrow: &
S                         E

This chain tells us that whenever O or S is selected, everything after those variables must occur. A is offered, F is offered, and E is not offered. So, we get:

O :arrow: F
S :arrow: F
O :arrow: E
S :arrow: E

All of those inferences come from the chain connecting the last rule to the first rule, and that is how you diagram those "and" and "or" chains. Draw your conditional arrows pointing right from the conjunction, with the variables stacked vertically to allow you to make additional chains more easily.

I hope that helps clarify that for you!
 Katya W
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#74445
Hi, would you guys mind showing me a visual diagram representation that shows that F could be true if L was offered? I’m having a really hard time visualizing it for some reason and finding the connection. Thank you so much!

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