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 Dave Killoran
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#72702
This game is also discussed in our Podcast, at the 14:37 mark: LSAT Podcast Episode 37: The November 2019 LSAT Logic Games Section

Complete Question Explanation
(The complete setup for this game can be found here: https://forum.powerscore.com/lsat/viewtopic.php?t=31706)

The correct answer choice is (D)


If S is trained in month 4, the following initial setup occurs:

  • S :arrow: 4


    ___ ..... ___ ..... ___ ..... _S_ ..... ___ ..... _X_ ..... ___
     1 .....     2 .....    3 .....    4 .....    5 .....    6 .....    7

Consequently, the QT block must be in months 1-2 or months 2-3, and the remaining month in the first three must be empty. That forces the U :longline: R sequence to occupy months 5 and 7:

  • S :arrow: 4


    ..... QT / X
    ___ ..... ___ ..... ___ ..... _S_ ..... _U_ ..... _X_ ..... _R_
     1 .....     2 .....    3 .....    4 .....    5 .....    6 .....    7
Consequently, answer choice (D) must be true and is correct.



Answer choice (A): This answer choice could be true but does not have to be true.

Answer choice (B): This answer choice could be true but does not have to be true.

Answer choice (C): This answer choice could be true but does not have to be true.

Answer choice (D): This is the correct answer.

Answer choice (E): This answer choice can never occur.
 CodeyD29
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#81477
Why must the remaining month of the QT sequence be empty?
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 KelseyWoods
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#81507
Hi Codey!

Rule #4 is that Shaw is the 3rd agent trained. So if Q & T have to come before S, then they have to be the only two agents before S so that S can still be the 3rd agent trained. If we tried to put Q, T, & U in those first 3 slots, that would make S the 4th agent trained. Put another way, S can only ever have 2 agents before it so that means that if S is 4th, one of those first 3 slots must be empty.

Hope this helps!

Best,
Kelsey

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