- PowerScore Staff
- Posts: 5852
- Joined: Mar 25, 2011
- Tue Oct 15, 2019 4:35 pm
#71207
This game is discussed in our Podcast: LSAT Podcast Episode 31: The September 2019 LSAT Logic Games Section
Complete Question Explanation
(The complete setup for this game can be found here: https://forum.powerscore.com/lsat/viewtopic.php?t=31299)
The correct answer choice is (B).
If J is not included in the display, the choice of kittens is reduced to F and then G or H. Thus, we are automatically in the 2 kittens/3 puppies scenario. Those kittens are displayed first and fifth (per the first rule), and the second, third, and fourth pens must contains puppies. This information immediately eliminates answer choice (A), because a kitten cannot be in the fourth pen.
The selection of puppies must be R, S, and T or W. But, if W were displayed, then G would have to be displayed second (from the fourth rule), which cannot happen here. Thus, the puppies must be R, S, and T. From the second rule we can infer that T must be third, and then R and S rotate in the second and fourth pens (the kittens then rotate between the first and fifth pens):
Answer choice (A): A kitten cannot be in the fourth pen and thus this answer choice in incorrect.
Answer choice (B): This is the correct answer choice. H could be in the fifth pen and F would then be in the first pen.
Answer choice (C): T must be in the third pen in this scenario.
Answer choice (D): T must be in the third pen in this scenario.
Answer choice (E): W cannot be displayed in this scenario.
Complete Question Explanation
(The complete setup for this game can be found here: https://forum.powerscore.com/lsat/viewtopic.php?t=31299)
The correct answer choice is (B).
If J is not included in the display, the choice of kittens is reduced to F and then G or H. Thus, we are automatically in the 2 kittens/3 puppies scenario. Those kittens are displayed first and fifth (per the first rule), and the second, third, and fourth pens must contains puppies. This information immediately eliminates answer choice (A), because a kitten cannot be in the fourth pen.
The selection of puppies must be R, S, and T or W. But, if W were displayed, then G would have to be displayed second (from the fourth rule), which cannot happen here. Thus, the puppies must be R, S, and T. From the second rule we can infer that T must be third, and then R and S rotate in the second and fourth pens (the kittens then rotate between the first and fifth pens):
- Name: _F/G/H_
_R/S_ _T_ _S/R_ _F/G/H_
P/K: _K_ _P_ _P_ _P_ _K_
1 2 3 4 5
Answer choice (A): A kitten cannot be in the fourth pen and thus this answer choice in incorrect.
Answer choice (B): This is the correct answer choice. H could be in the fifth pen and F would then be in the first pen.
Answer choice (C): T must be in the third pen in this scenario.
Answer choice (D): T must be in the third pen in this scenario.
Answer choice (E): W cannot be displayed in this scenario.
Dave Killoran
PowerScore Test Preparation
Follow me on Twitter at http://twitter.com/DaveKilloran
My LSAT Articles: http://blog.powerscore.com/lsat/author/dave-killoran
PowerScore PodCast: http://www.powerscore.com/lsat/podcast/
PowerScore Test Preparation
Follow me on Twitter at http://twitter.com/DaveKilloran
My LSAT Articles: http://blog.powerscore.com/lsat/author/dave-killoran
PowerScore PodCast: http://www.powerscore.com/lsat/podcast/