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(The complete setup for this game can be found here: lsat/viewtopic.php?t=11881)
The correct answer choice is (D)
This question asks you to suspend the second rule and replace it with a rule that has an identical effect. The second rule creates a minimum split block for the two Rs, so that limitation must be equalled by the correct answer. This immediately casts suspicion on an answer choice such as (C), which places just one business between the two restaurants.
Given that one of the Rs is always at the end of the row (from the first rule), what is the functional effect of the second rule? To place the other R at the other end of the row (spaces 3 and 4 in Template #1, and spaces 4 and 5 in Template #2). Thus, you need a replacement rule that keeps an R at that “opposite” end while not adding any further restrictions to R’s movement. Note that, just because the two templates when combined limit R to spaces 3, 4, and 5 does not mean answer choice (A) is correct. (A) actually allows for greater latitude for R than it currently has: R cannot currently be in space 5 in Template #1 or space 3 in Template #2. Thus, answer choice (A) cannot be correct.
To evaluate this question, consider what else you know about the other R. When it is on the other side of the row, is there any constant that appears in relation to the R? Yes, P is always at the other end of the row. Thus, look for an answer that links P and R, and determine whether that answer could possibly be correct.
Answer choice (D) is the only answer to feature P and R, and the result of this rule would be to keep the “second” R within three spaces of P at all times. This would restrict R to spaces 3 and 4 in Template #1, and spaces 4 and 5 in Template #2 (remember, O or V must always be next to P, so space 2 in Template #1 is always unavailable, and space 6 in Template #2 is unavailable). That is the identical effect as the second rule, and thus answer choice (D) is a perfect equivalent to that rule, and therefore the correct answer.