## # 19 - When an ordinary piece of steel is put under pressure

LSAT2018
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I couldn't find an answer for this question because I was trying to base the answer on the statement in the stimulus that the glass volume remains unchanged.
How answer (E) correct?
Shannon Parker
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LSAT2018 wrote:I couldn't find an answer for this question because I was trying to base the answer on the statement in the stimulus that the glass volume remains unchanged.
How answer (E) correct?

I can see where that got confusing. Although answer choice E does not specifically state that the overall volume of the glass will remain unchanged, it describes what will occur, and does not indicate that the volume will change so it does not violate the rule.

Glass is fluid, so it flows away from the pressure. If you place heavy object in the middle of the glass it will create pressure. The glass will flow away from the heavy object making that portion of it thinner. The overall volume of the glass remains unchanged during this process.

Hope this helps.
Shannon
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I don't understand why A is incorrect. Because glass is fluid, I figured it would have to be of uniform thickness. "A" says the glass becomes larger in size yet is still uniform in thickness. In order for the volume to remain the same (as required by the stimulus) the glass could be larger in size and thinner in thickness.