This is a Grouping: Defined-Fixed, Unbalanced: Overloaded game.

This game was widely regarded as the most difficult game of the exam, and as one of the hardest games in recent years. This is definitely a difficult game, and the test makers repeatedly force students to Hurdle the Uncertainty, which is one of the more challenging principles that appears in Logic Games.

The initial scenario appears as follows:

Of immediate interest is the fact that exactly five dinosaurs are displayed, and exactly two dinosaurs are not displayed. Thus, any time two dinosaurs are not on display, the other five automatically are on display.

The first rule helpfully establishes that exactly two of the toys are mauve:

With exactly two mauve toys, the remaining toys must be green, red, or yellow.

The second rule includes S in the display, and stipulates that S is red;

This is a powerful rule, and it reduces the remainder of the game into a 6-into-4 scenario.

The third and fourth rules are similar, and both are conditional:

In both cases, if the dinosaur is included in the display, then it is a specific color (but do not reverse the rules. For example, if a dinosaur is green, it does not have to be I). These two rules can also be combined with the first rule to determine that neither I nor P can be one of the two mauve toys:

Because S is already known to be red from the second rule, the pool of candidates for the two mauve dinosaurs is down to L, T, U, and V. This fact will become critical shortly.

The fifth rule further reduces the pool of available dinosaurs:

- V U

The sixth rule also creates further limitations:

Given that only L, T, U, and V are available for the two mauve toy slots, and that the fifth and sixth rules both address members of this group, one should suspect that some powerful inferences can be made about the mauve dinosaurs.

Because both L and U cannot be mauve, the candidate pool for the two mauve dinosaurs appears as L/U, T, and V. Thus, if either T or V is removed, the other must be displayed, and then one of L and U must be displayed. For example, If V is removed from the display, then T and L/U must be the two mauve toys on display.

Of course, the fifth rule also has a similar restriction, because V and U cannot be displayed. So, if either V or U is displayed, the other is knocked out, and the remaining options are limited. For example, if U is included in the display, then V cannot be included in the display, forcing T to be mauve (L or U could still be the other mauve dinosaur).

The sixth rule produces another inference, namely that if I and P are both selected, L and U cannot both be selected (because then L and U would both have to be mauve, a violation). This inference can be diagrammed as:

This final inference plays only a minor role in the game. The main key to the game is understanding that the two mauve dinosaurs must be selected from the pool of L/U, T, and V. Identify this limitation, and the game is manageable. Fail to identify it, and the game seems nightmarishly difficult.

With the prior information, and the additional note that T is a random, we arrive at the final setup to the game:

Note: Additional Not Laws, such as no further mauve toys can be displayed, could be shown, but seem unnecessary given the focus on that rule.